Internal Questions:
1. In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water
Solution: We have,
Sodium carbonate (Na2CO3) + Acetic acid (CH3COOH
) → Sodium acetate (CH3COONa
) + Carbon dioxide (CO2
) + Water (H2O
)
Here, Sodium carbonate (Na2CO3) = 5.3 g
Acetic acid (CH3COOH) = 6 g
Sodium acetate (CH3COONa) = 8.2 g
Carbon dioxide (CO2) = 2.2 g
Water (H2O) = 0.9
LHS : Sodium carbonate (Na2CO3) + Acetic acid (CH3COOH
)
= 5.3 g + 6 g
=11.3 g
RHS : Sodium acetate (CH3COONa) + Carbon dioxide (CO2
) + Water (H2O
)
= 8.2 g + 2.2 g + 0.9 g
=11.3 g
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