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Chapter 26. Introduction to Probability NIOS Class 10 Mathematics Chapter-Wise Important Questions and Answers

Chapter 26. Introduction to Probability | NIOS Class 10 Mathematics Important Questions, Fully Solved Answers, and Chapter-wise Exam Preparation Guide.

Chapter 26. INTRODUCTION TO PROBABILITY

Multiple Choose Questions and Answers for Introduction to Probability [1 Mark]

Question: If  , then P(E) =

(a)  0     (b)  – 1    (c)  1     (d) 0.5  

Answer:   (c)  1

[ Here,  

We have,  

   ]

Question: The sum of the probabilities of all the elementary events of an experiment is ..............

(a)  – 1     (b) 1      (c) 0.2       (d) 0.5  

Answer:  (b) 1

Question: Which of the following can not be the probability of an event?

(A)     (B) – 1.01   (C) 12%    (D) 0.3

Answer:   (B)  – 1.01

[ A probability always lies between 0 and 1, i.e.,   ]

Question: A card is selected at random from a well shuffled deck of 52 playing cards. The probability of its being a face card is
(A)   
       (B)       (C)       (D) 
Answer:   (A)    

[  The number of face cards = 12

   ]

Question: If an event cannot occur, then its probability is
         (A) 1          (B)   
                (C)             (D) 0
Answer:   (D)  0

Question: Which of the following cannot be the probability of an event?
         (A)               (B)  0.1              (C) 3%           (D)    
Answer:   (D)   

[ We hve,  ]

Question: In a single throw of two dice, the probability of getting the sum 2 is

(A)      (B)         (C)         (D)  

Answer:  (C)          

[ Total number of possible outcomes = 6 × 6 = 36

The number of favourable outcomes  = 1 [(1,1)

   ]

Question: In a simultaneous toss of two coins, the probability of getting one head and one tail is

(A)      (B)          (C)      (D)    

Answer:  (C)   

[ Total number of possible outcomes = 4 [ HH , HT , TH , TT ]

The number of favourable outcomes = 2 [HT,TH]

Therefore,]

Question: If   , then the probability of ‘not E’ is

(a)       (b)   (c)        (d)   

Answer:  (c)         

 [ We have,   ]

Question: If P(A) denotes the probability of an event A, then
      (A) P(A) < 0      (B)  P(A) > 1       (C)    0 ≤ P(A) ≤ 1          (D) –1 ≤ P(A) ≤ 1
Answer:   (C)    0 ≤ P(A) ≤ 1   .      

Short Questions and Answers for Introduction to Probability [1 or 2 Marks]

Question:  A card is drawn at random from a well-shuffled deck of 52 cards. Find the probability that this card is a face card.

Solution:  Number of all possible outcomes = 52

Number of outcomes favourable to the Event E “a face card” = 3 × 4 = 12 [Kings, queens, and jacks are face cards]

 

Question: A coin is tossed two times. What is the probability of getting a head each time?

Solution: The number of possible outcomes = 4  [ HH , HT , TH , TT ]

Let E be the event “getting head each time”.  

Question: Two different coins are tossed at the same time. Write down all possible outcomes. What is the probability of getting head on one and tail on the other coin?

Solution:  The total number of possible outcomes = 4.  [HH,HT,TH,TT]      

The number of outcomes favourable to the Event E “head on one and tail on the other coin” = 4 – 2 = 2 . [HT,TH]

  

Question: A coin is tossed once. Find the probability of getting (i) a head, (ii) a tail.

Solution: Number of possible outcomes = 2 [H,T]

(i) Let E be the event “getting a head”.

Number of outcomes favourable to E = 1 (i.e., H)

  

(i) Let E be the event “getting a tail”.

Number of outcomes favourable to E = 1 (i.e., T)

    

Question: A die is thrown once. What is the probability of getting a number 3?

Solution: Let E be the event “getting a number 3”.

Number of possible outcomes = 6 [1, 2, 3, 4, 5, 6 ]

Number of outcomes favourable to E = 1 (i.e., 3)

    

Question: 10 defective rings are accidentally mixed with 100 good ones in a lot. It is not possible to just look at a ring and tell whether or not it is defective. One ring is drawn at random from this lot. What is the probability of this ring to be a good one?

Solution: Number of all possible outcomes = 10 + 100 = 110

Number of outcomes favourable to the event E “ ring is good one” = 100 

Long Questions and Answers for Introduction to Probability [ 3 or 4 Mark]

Question: A card is drawn from a well shuffled deck of 52 playing cards. Find the probability that it is of (i) red colour (ii) black colour

Solution:  (i) Let E be the event that the card drawn is of red colour.

Number of cards of red colour = 13 + 13 = 26  [13 Diamonds and 13 Hearts]

So, the number of favourable outcomes to E = 26

Total number of cards = 52

 

(ii) Let F be the event that the card drawn is of black colour.

 Number of cards of black colour = 13 + 13 = 26 [13 Spades and 13 Clubs ]

 

Question: A bag contains 3 red and 5 white balls. A ball is drawn from the bag without looking into it. What is the probability of this ball to be of (i) red colour (ii) white colour?

Solution: Total number of ball = 3 + 5 = 8 .

(i) The number of red balls = 3

 

(ii) The number of white balls = 5

 

Question: A bag contains 15 white balls and 10 blue balls. A ball is drawn at random from the bag. What is the probability of drawing

(i) a ball of not blue colour (ii) a ball not of white colour

Solution: Total number of balls = 15 + 10 = 25

(i) The number of outcomes favourable to the Event E “a ball of not blue colour” = 25 – 10 = 15 .

 

(ii) The number of outcomes favourable to the Event E “a ball not of white colour” = 25 – 15 = 10 .

 

Question: A bag contains 15 red balls and some green balls. If the probability of drawing a green ball is , find the number of green balls.

Solution: Let x the number of green balls .

Total number of balls

A/Q, 

   

Therefore, the number of green ball is 3 .

Question: Two dice are thrown simultaneously and the sum of the numbers appearing on them is noted. What is the probability that the sum is

 (a) 9      (b) 10    (c) 12

Solution: The total number of possible outcomes = 6 × 6 = 36.    

The sample space = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

 (a) The number of outcomes favourable to the Event E “the sum of 9” = 4 [(3,6) ,(4,5),(5,4),(6,3)] .

 

(b) The number of outcomes favourable to the Event E “the sum of 10” = 3 [(4,6),(5,5),(6,4)] .

(c) The number of outcomes favourable to the Event E “the sum of 12” = 1 [(6,6)] .


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