Chapter 12. Concurrent Lines NIOS Class 10 Mathematics Chapter-Wise Important Questions and Answers

Chapter 12. Concurrent Lines | NIOS Class 10 Mathematics Important Questions, Fully Solved Answers, and Chapter-wise Exam Preparation Guide.

Chapter 12. CONCURRENT LINES

Optional Questions and Answers for Algebraic Expressions and Polynomials [1 Mark]

CHECK YOUR PROGRESS 3.1

Short Questions and Answers for Algebraic Expressions and Polynomials [1 or 2 Marks]

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Long Questions and Answers for Algebraic Expressions and Polynomials [ 3 or 4 Mark]

CHECK YOUR PROGRESS 12.1

1. In the given figure BF = FC , ∠BAE = ∠CAE and ∠ADE = ∠GFC = 90° , then name a median, an angle bisector, an altitude and a perpendicular bisector of the triangle.

Fig. 12.25

Solution: Since, AF is a median

So,  BF = FC 

 AE is an angle bisector of ∠BAC .

So,  ∠BAE = ∠CAE  

Again,  AD⊥BC and  GF⊥BC

  ∠ADE = ∠GFC = 90°

So, AD and GF are an altitude of triangle ABC .

F is a mid-point of BC and also ∠GFC = 90°

So, ∠GFB =∠GFC = 90°  

Therefore,GF is a perpendicular bisector .

 

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Posted 1 month ago