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Chapter 10. Lines and Angles NIOS Class 10 Mathematics Chapter-Wise Important Questions and Answers

Chapter 10. Lines and Angles | NIOS Class 10 Mathematics Important Questions, Fully Solved Answers, and Chapter-wise Exam Preparation Guide.

Chapter 10. LINES AND ANGLES

Optional Questions and Answers for Algebraic Expressions and Polynomials [1 Mark]

CHECK YOUR PROGRESS 3.1

Short Questions and Answers for Algebraic Expressions and Polynomials [1 or 2 Marks]

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Long Questions and Answers for Algebraic Expressions and Polynomials [ 3 or 4 Mark]

CHECK YOUR PROGRESS 10.1.

1. Choose the correct answer out of the given alternatives in the following multiple choice questions :

Photo

Fig. 10.29

In Fig. 10.29, AB || CD and PQ intersects them at R and S respectively.

(i) ARS and BRS form

(A) a pair of alternate angles

(B) a linear pair

(C) a pair of corresponding angles

(D) a pair of vertically opposite angles

Solution: (B) a linear pair .

[ Since, AB || CD and PQ intersects them at R and S respectively.

ARS  and BRS (A linear pair of angles) ]

 

(ii) ARS and RSD form a pair of

(A) Alternate angles   (B) Vertically opposite angles   (C) Corresponding angles   (D) Interior angles

Solution:  (A) Alternate angles .

[ Since, AB||CD and PQ intersects them at R and S respectively.

  ARS =RSD (Alternate angles)  ]

 

(iii) If PRB = 60° , then QSC is

(A) 120°      (B) 60°     (C) 30°     (D) 90°

Solution: (B) 60°

[ Since, AB || CD and PQ intersects them at R and S respectively .

 ∠PRB=∠QSC=60° ]

(iv) In Fig. 10.30 above, AB and CD intersect at O. COB is equal to

    (A) 36°      (B) 72°    (C) 108°    (D) 144°

Photo fig.10.30

Solution: (C) 108° 

[ Since,  ∠COB+∠BOD=180°

⇒∠COB+72°=180°

⇒∠COB=180°-72°=108°  ]

 

2. In Fig. 10.31 above, AB is a straight line. Find x

Photo 10.31

Solution: Given, ∠AOC=5x+10° and ∠BOC=5x 

Since, AB is a straight line .

 ∠AOC+∠BOC=180°

5x+10°+5x=180°

⇒5x+10°+5x°=180°

⇒10x=180°-10°=170°

⇒x=170°10=17°

⇒x=17°

3. In Fig. 10.32 below, l is parallel to m. Find angles 1 to 7.

Photo Fig. 10.32

Solution: Since, l is parallel to m .

∠1+70°=180° (linear pair of angles)

⇒∠1=180°-70°

⇒∠1=110° 

∠2=70° (vertically opposite angles)

∠1=∠3=110° (vertically opposite angles)

∠3=∠4=110° [Alternate interior angles]

∠2=∠5=70°  [Alternate interior angles]

∠4=∠6=110° (vertically opposite angles)

And  ∠5=∠7=70° (vertically opposite angles)


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